7(2x-1)=2(3x-2)-3(4x-3)

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Solution for 7(2x-1)=2(3x-2)-3(4x-3) equation: 



7(2x-1)=2(3x-2)-3(4x-3)

We move all terms to the left:

7(2x-1)-(2(3x-2)-3(4x-3))=0

We multiply parentheses

14x-(2(3x-2)-3(4x-3))-7=0



We calculate terms in parentheses: -(2(3x-2)-3(4x-3)), so:

2(3x-2)-3(4x-3)

We multiply parentheses

6x-12x-4+9

We add all the numbers together, and all the variables

-6x+5

Back to the equation:

-(-6x+5)



We get rid of parentheses

14x+6x-5-7=0

We add all the numbers together, and all the variables

20x-12=0

We move all terms containing x to the left, all other terms to the right

20x=12

x=12/20

x=3/5

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