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3x^2-2x+4=1-2x
We move all terms to the left:
3x^2-2x+4-(1-2x)=0
We add all the numbers together, and all the variables
3x^2-2x-(-2x+1)+4=0
We get rid of parentheses
3x^2-2x+2x-1+4=0
We add all the numbers together, and all the variables
3x^2+3=0
a = 3; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·3·3
Δ = -36
Delta is less than zero, so there is no solution for the equation
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