7(2x-1)-3(4x-1)=4(3x+2)-1

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Solution for 7(2x-1)-3(4x-1)=4(3x+2)-1 equation: 



7(2x-1)-3(4x-1)=4(3x+2)-1

We move all terms to the left:

7(2x-1)-3(4x-1)-(4(3x+2)-1)=0

We multiply parentheses

14x-12x-(4(3x+2)-1)-7+3=0



We calculate terms in parentheses: -(4(3x+2)-1), so:

4(3x+2)-1

We multiply parentheses

12x+8-1

We add all the numbers together, and all the variables

12x+7

Back to the equation:

-(12x+7)



We add all the numbers together, and all the variables

2x-(12x+7)-4=0

We get rid of parentheses

2x-12x-7-4=0

We add all the numbers together, and all the variables

-10x-11=0

We move all terms containing x to the left, all other terms to the right

-10x=11

x=11/-10

x=-1+1/10

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