33x+1,117x-21=23(50x+50)

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Solution for 33x+1,117x-21=23(50x+50) equation: 



33x+1.117x-21=23(50x+50)

We move all terms to the left:

33x+1.117x-21-(23(50x+50))=0

We add all the numbers together, and all the variables

34.117x-(23(50x+50))-21=0



We calculate terms in parentheses: -(23(50x+50)), so:

23(50x+50)

We multiply parentheses

1150x+1150

Back to the equation:

-(1150x+1150)



We get rid of parentheses

34.117x-1150x-1150-21=0

We add all the numbers together, and all the variables

-1115.883x-1171=0

We move all terms containing x to the left, all other terms to the right

-1115.883x=1171

x=1171/-1115.883

x=-1+10.771350400625/218.07367598202

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