7(2x+1)-(8x-1)=68

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Solution for 7(2x+1)-(8x-1)=68 equation: 



7(2x+1)-(8x-1)=68

We move all terms to the left:

7(2x+1)-(8x-1)-(68)=0

We multiply parentheses

14x-(8x-1)+7-68=0

We get rid of parentheses

14x-8x+1+7-68=0

We add all the numbers together, and all the variables

6x-60=0

We move all terms containing x to the left, all other terms to the right

6x=60

x=60/6

x=10

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