n=12+3(n-1)

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Solution for n=12+3(n-1) equation: 



n=12+3(n-1)

We move all terms to the left:

n-(12+3(n-1))=0



We calculate terms in parentheses: -(12+3(n-1)), so:

12+3(n-1)

determiningTheFunctionDomain
3(n-1)+12

We multiply parentheses

3n-3+12

We add all the numbers together, and all the variables

3n+9

Back to the equation:

-(3n+9)



We get rid of parentheses

n-3n-9=0

We add all the numbers together, and all the variables

-2n-9=0

We move all terms containing n to the left, all other terms to the right

-2n=9

n=9/-2

n=-4+1/2

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