7(2t+-4)=3(7t-2)-8

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Solution for 7(2t+-4)=3(7t-2)-8 equation: 



7(2t+-4)=3(7t-2)-8

We move all terms to the left:

7(2t+-4)-(3(7t-2)-8)=0

We add all the numbers together, and all the variables

7(2t-4)-(3(7t-2)-8)=0

We multiply parentheses

14t-(3(7t-2)-8)-28=0



We calculate terms in parentheses: -(3(7t-2)-8), so:

3(7t-2)-8

We multiply parentheses

21t-6-8

We add all the numbers together, and all the variables

21t-14

Back to the equation:

-(21t-14)



We get rid of parentheses

14t-21t+14-28=0

We add all the numbers together, and all the variables

-7t-14=0

We move all terms containing t to the left, all other terms to the right

-7t=14

t=14/-7

t=-2

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