7(2r+5)=3(1+6r)

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Solution for 7(2r+5)=3(1+6r) equation:



7(2r+5)=3(1+6r)
We move all terms to the left:
7(2r+5)-(3(1+6r))=0
We add all the numbers together, and all the variables
7(2r+5)-(3(6r+1))=0
We multiply parentheses
14r-(3(6r+1))+35=0
We calculate terms in parentheses: -(3(6r+1)), so:
3(6r+1)
We multiply parentheses
18r+3
Back to the equation:
-(18r+3)
We get rid of parentheses
14r-18r-3+35=0
We add all the numbers together, and all the variables
-4r+32=0
We move all terms containing r to the left, all other terms to the right
-4r=-32
r=-32/-4
r=+8

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