8(2x-2)=-8x+8(2x+5)

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Solution for 8(2x-2)=-8x+8(2x+5) equation: 



8(2x-2)=-8x+8(2x+5)

We move all terms to the left:

8(2x-2)-(-8x+8(2x+5))=0

We multiply parentheses

16x-(-8x+8(2x+5))-16=0



We calculate terms in parentheses: -(-8x+8(2x+5)), so:

-8x+8(2x+5)

We multiply parentheses

-8x+16x+40

We add all the numbers together, and all the variables

8x+40

Back to the equation:

-(8x+40)



We get rid of parentheses

16x-8x-40-16=0

We add all the numbers together, and all the variables

8x-56=0

We move all terms containing x to the left, all other terms to the right

8x=56

x=56/8

x=7

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