7(2r+3)=7r-6

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Solution for 7(2r+3)=7r-6 equation: 



7(2r+3)=7r-6

We move all terms to the left:

7(2r+3)-(7r-6)=0

We multiply parentheses

14r-(7r-6)+21=0

We get rid of parentheses

14r-7r+6+21=0

We add all the numbers together, and all the variables

7r+27=0

We move all terms containing r to the left, all other terms to the right

7r=-27

r=-27/7

r=-3+6/7

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