7(2p+3)+5=19-3(p+6)

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Solution for 7(2p+3)+5=19-3(p+6) equation: 



7(2p+3)+5=19-3(p+6)

We move all terms to the left:

7(2p+3)+5-(19-3(p+6))=0

We multiply parentheses

14p-(19-3(p+6))+21+5=0



We calculate terms in parentheses: -(19-3(p+6)), so:

19-3(p+6)

determiningTheFunctionDomain
-3(p+6)+19

We multiply parentheses

-3p-18+19

We add all the numbers together, and all the variables

-3p+1

Back to the equation:

-(-3p+1)



We add all the numbers together, and all the variables

14p-(-3p+1)+26=0

We get rid of parentheses

14p+3p-1+26=0

We add all the numbers together, and all the variables

17p+25=0

We move all terms containing p to the left, all other terms to the right

17p=-25

p=-25/17

p=-1+8/17

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