-36+2w=-8w(w+3)

Solution for -36+2w=-8w(w+3) equation:

-36+2w=-8w(w+3)

We move all terms to the left:

-36+2w-(-8w(w+3))=0


We calculate terms in parentheses: -(-8w(w+3)), so:

-8w(w+3)

We multiply parentheses

-8w^2-24w

Back to the equation:

-(-8w^2-24w)


We get rid of parentheses

8w^2+24w+2w-36=0

We add all the numbers together, and all the variables

8w^2+26w-36=0

a = 8; b = 26; c = -36;
Δ = b2-4ac
Δ = 262-4·8·(-36)
Δ = 1828
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1828}=\sqrt{4*457}=\sqrt{4}*\sqrt{457}=2\sqrt{457}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{457}}{2*8}=\frac{-26-2\sqrt{457}}{16}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{457}}{2*8}=\frac{-26+2\sqrt{457}}{16}
$