7(2n+4)=6(4n+4)+8

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Solution for 7(2n+4)=6(4n+4)+8 equation:



7(2n+4)=6(4n+4)+8
We move all terms to the left:
7(2n+4)-(6(4n+4)+8)=0
We multiply parentheses
14n-(6(4n+4)+8)+28=0
We calculate terms in parentheses: -(6(4n+4)+8), so:
6(4n+4)+8
We multiply parentheses
24n+24+8
We add all the numbers together, and all the variables
24n+32
Back to the equation:
-(24n+32)
We get rid of parentheses
14n-24n-32+28=0
We add all the numbers together, and all the variables
-10n-4=0
We move all terms containing n to the left, all other terms to the right
-10n=4
n=4/-10
n=-2/5

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