7(2m-1)-35m=65(4-3m)

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Solution for 7(2m-1)-35m=65(4-3m) equation: 



7(2m-1)-35m=65(4-3m)

We move all terms to the left:

7(2m-1)-35m-(65(4-3m))=0

We add all the numbers together, and all the variables

7(2m-1)-35m-(65(-3m+4))=0

We add all the numbers together, and all the variables

-35m+7(2m-1)-(65(-3m+4))=0

We multiply parentheses

-35m+14m-(65(-3m+4))-7=0



We calculate terms in parentheses: -(65(-3m+4)), so:

65(-3m+4)

We multiply parentheses

-195m+260

Back to the equation:

-(-195m+260)



We add all the numbers together, and all the variables

-21m-(-195m+260)-7=0

We get rid of parentheses

-21m+195m-260-7=0

We add all the numbers together, and all the variables

174m-267=0

We move all terms containing m to the left, all other terms to the right

174m=267

m=267/174

m=1+31/58

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