7(2m-1)-35m=6(4-3m)

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Solution for 7(2m-1)-35m=6(4-3m) equation:



7(2m-1)-35m=6(4-3m)
We move all terms to the left:
7(2m-1)-35m-(6(4-3m))=0
We add all the numbers together, and all the variables
7(2m-1)-35m-(6(-3m+4))=0
We add all the numbers together, and all the variables
-35m+7(2m-1)-(6(-3m+4))=0
We multiply parentheses
-35m+14m-(6(-3m+4))-7=0
We calculate terms in parentheses: -(6(-3m+4)), so:
6(-3m+4)
We multiply parentheses
-18m+24
Back to the equation:
-(-18m+24)
We add all the numbers together, and all the variables
-21m-(-18m+24)-7=0
We get rid of parentheses
-21m+18m-24-7=0
We add all the numbers together, and all the variables
-3m-31=0
We move all terms containing m to the left, all other terms to the right
-3m=31
m=31/-3
m=-10+1/3

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