7(2l+1)=133

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Solution for 7(2l+1)=133 equation: 



7(2l+1)=133

We move all terms to the left:

7(2l+1)-(133)=0

We multiply parentheses

14l+7-133=0

We add all the numbers together, and all the variables

14l-126=0

We move all terms containing l to the left, all other terms to the right

14l=126

l=126/14

l=9

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