-3(2x-5)+7x-14-4+2(10+2x)=18-11x+4(2-x+4x)-0.05x+0.50x-19

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Solution for -3(2x-5)+7x-14-4+2(10+2x)=18-11x+4(2-x+4x)-0.05x+0.50x-19 equation: 



-3(2x-5)+7x-14-4+2(10+2x)=18-11x+4(2-x+4x)-0.05x+0.50x-19

We move all terms to the left:

-3(2x-5)+7x-14-4+2(10+2x)-(18-11x+4(2-x+4x)-0.05x+0.50x-19)=0

We add all the numbers together, and all the variables

-3(2x-5)+7x+2(2x+10)-(18-11x+4(3x+2)-0.05x+0.50x-19)-14-4=0

We add all the numbers together, and all the variables

7x-3(2x-5)+2(2x+10)-(18-11x+4(3x+2)-0.05x+0.50x-19)-18=0

We multiply parentheses

7x-6x+4x-(18-11x+4(3x+2)-0.05x+0.50x-19)+15+20-18=0



We calculate terms in parentheses: -(18-11x+4(3x+2)-0.05x+0.50x-19), so:

18-11x+4(3x+2)-0.05x+0.50x-19

determiningTheFunctionDomain
-11x+4(3x+2)-0.05x+0.50x+18-19

We add all the numbers together, and all the variables

-10.55x+4(3x+2)-1

We multiply parentheses

-10.55x+12x+8-1

We add all the numbers together, and all the variables

1.45x+7

Back to the equation:

-(1.45x+7)



We add all the numbers together, and all the variables

5x-(1.45x+7)+17=0

We get rid of parentheses

5x-1.45x-7+17=0

We add all the numbers together, and all the variables

3.55x+10=0

We move all terms containing x to the left, all other terms to the right

3.55x=-10

x=-10/3.55

x=-2+2.9/3.55

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