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7(2+x)=35+5(x-1.2)
We move all terms to the left:
7(2+x)-(35+5(x-1.2))=0
We add all the numbers together, and all the variables
7(x+2)-(35+5(x-1.2))=0
We multiply parentheses
7x-(35+5(x-1.2))+14=0
We calculate terms in parentheses: -(35+5(x-1.2)), so:We get rid of parentheses
35+5(x-1.2)
determiningTheFunctionDomain 5(x-1.2)+35
We multiply parentheses
5x-6+35
We add all the numbers together, and all the variables
5x+29
Back to the equation:
-(5x+29)
7x-5x-29+14=0
We add all the numbers together, and all the variables
2x-15=0
We move all terms containing x to the left, all other terms to the right
2x=15
x=15/2
x=7+1/2
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