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1/5(15c+10)=c+7
We move all terms to the left:
1/5(15c+10)-(c+7)=0
Domain of the equation: 5(15c+10)!=0We get rid of parentheses
c∈R
1/5(15c+10)-c-7=0
We multiply all the terms by the denominator
-c*5(15c+10)-7*5(15c+10)+1=0
Wy multiply elements
-5c^2(1-35c(1+1=0
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