7(2+2n)-4(n+3)=-78

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Solution for 7(2+2n)-4(n+3)=-78 equation: 



7(2+2n)-4(n+3)=-78

We move all terms to the left:

7(2+2n)-4(n+3)-(-78)=0

We add all the numbers together, and all the variables

7(2n+2)-4(n+3)-(-78)=0

We add all the numbers together, and all the variables

7(2n+2)-4(n+3)+78=0

We multiply parentheses

14n-4n+14-12+78=0

We add all the numbers together, and all the variables

10n+80=0

We move all terms containing n to the left, all other terms to the right

10n=-80

n=-80/10

n=-8

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