-4(2x-5)=3x+28+1x+16

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Solution for -4(2x-5)=3x+28+1x+16 equation: 



-4(2x-5)=3x+28+1x+16

We move all terms to the left:

-4(2x-5)-(3x+28+1x+16)=0

We add all the numbers together, and all the variables

-4(2x-5)-(4x+44)=0

We multiply parentheses

-8x-(4x+44)+20=0

We get rid of parentheses

-8x-4x-44+20=0

We add all the numbers together, and all the variables

-12x-24=0

We move all terms containing x to the left, all other terms to the right

-12x=24

x=24/-12

x=-2

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