7(12-y)=9(y+3)

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Solution for 7(12-y)=9(y+3) equation: 



7(12-y)=9(y+3)

We move all terms to the left:

7(12-y)-(9(y+3))=0

We add all the numbers together, and all the variables

7(-1y+12)-(9(y+3))=0

We multiply parentheses

-7y-(9(y+3))+84=0



We calculate terms in parentheses: -(9(y+3)), so:

9(y+3)

We multiply parentheses

9y+27

Back to the equation:

-(9y+27)



We get rid of parentheses

-7y-9y-27+84=0

We add all the numbers together, and all the variables

-16y+57=0

We move all terms containing y to the left, all other terms to the right

-16y=-57

y=-57/-16

y=3+9/16

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