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2x(x-3)=x-16
We move all terms to the left:
2x(x-3)-(x-16)=0
We multiply parentheses
2x^2-6x-(x-16)=0
We get rid of parentheses
2x^2-6x-x+16=0
We add all the numbers together, and all the variables
2x^2-7x+16=0
a = 2; b = -7; c = +16;
Δ = b2-4ac
Δ = -72-4·2·16
Δ = -79
Delta is less than zero, so there is no solution for the equation
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