7(1-y)=-3y-2

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Solution for 7(1-y)=-3y-2 equation: 



7(1-y)=-3y-2

We move all terms to the left:

7(1-y)-(-3y-2)=0

We add all the numbers together, and all the variables

7(-1y+1)-(-3y-2)=0

We multiply parentheses

-7y-(-3y-2)+7=0

We get rid of parentheses

-7y+3y+2+7=0

We add all the numbers together, and all the variables

-4y+9=0

We move all terms containing y to the left, all other terms to the right

-4y=-9

y=-9/-4

y=2+1/4

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