(10+2x)(12+2x)=224

Solution for (10+2x)(12+2x)=224 equation:

(10+2x)(12+2x)=224

We move all terms to the left:

(10+2x)(12+2x)-(224)=0

We add all the numbers together, and all the variables

(2x+10)(2x+12)-224=0

We multiply parentheses ..

(+4x^2+24x+20x+120)-224=0

We get rid of parentheses

4x^2+24x+20x+120-224=0

We add all the numbers together, and all the variables

4x^2+44x-104=0

a = 4; b = 44; c = -104;
Δ = b2-4ac
Δ = 442-4·4·(-104)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-60}{2*4}=\frac{-104}{8}
=-13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+60}{2*4}=\frac{16}{8}
=2
$