7(1-x)+3x=8(2x-5)-3(3+4x)

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Solution for 7(1-x)+3x=8(2x-5)-3(3+4x) equation: 



7(1-x)+3x=8(2x-5)-3(3+4x)

We move all terms to the left:

7(1-x)+3x-(8(2x-5)-3(3+4x))=0

We add all the numbers together, and all the variables

7(-1x+1)+3x-(8(2x-5)-3(4x+3))=0

We add all the numbers together, and all the variables

3x+7(-1x+1)-(8(2x-5)-3(4x+3))=0

We multiply parentheses

3x-7x-(8(2x-5)-3(4x+3))+7=0



We calculate terms in parentheses: -(8(2x-5)-3(4x+3)), so:

8(2x-5)-3(4x+3)

We multiply parentheses

16x-12x-40-9

We add all the numbers together, and all the variables

4x-49

Back to the equation:

-(4x-49)



We add all the numbers together, and all the variables

-4x-(4x-49)+7=0

We get rid of parentheses

-4x-4x+49+7=0

We add all the numbers together, and all the variables

-8x+56=0

We move all terms containing x to the left, all other terms to the right

-8x=-56

x=-56/-8

x=+7

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