-2(x-2)+x=5-(-x+3)

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Solution for -2(x-2)+x=5-(-x+3) equation: 



-2(x-2)+x=5-(-x+3)

We move all terms to the left:

-2(x-2)+x-(5-(-x+3))=0

We add all the numbers together, and all the variables

-2(x-2)+x-(5-(-1x+3))=0

We add all the numbers together, and all the variables

x-2(x-2)-(5-(-1x+3))=0

We multiply parentheses

x-2x-(5-(-1x+3))+4=0



We calculate terms in parentheses: -(5-(-1x+3)), so:

5-(-1x+3)

determiningTheFunctionDomain
-(-1x+3)+5

We get rid of parentheses

1x-3+5

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)



We add all the numbers together, and all the variables

-1x-(x+2)+4=0

We get rid of parentheses

-1x-x-2+4=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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