7(1-n)+3n=5(3n-4)

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Solution for 7(1-n)+3n=5(3n-4) equation: 



7(1-n)+3n=5(3n-4)

We move all terms to the left:

7(1-n)+3n-(5(3n-4))=0

We add all the numbers together, and all the variables

7(-1n+1)+3n-(5(3n-4))=0

We add all the numbers together, and all the variables

3n+7(-1n+1)-(5(3n-4))=0

We multiply parentheses

3n-7n-(5(3n-4))+7=0



We calculate terms in parentheses: -(5(3n-4)), so:

5(3n-4)

We multiply parentheses

15n-20

Back to the equation:

-(15n-20)



We add all the numbers together, and all the variables

-4n-(15n-20)+7=0

We get rid of parentheses

-4n-15n+20+7=0

We add all the numbers together, and all the variables

-19n+27=0

We move all terms containing n to the left, all other terms to the right

-19n=-27

n=-27/-19

n=1+8/19

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