7(-2+4x)+6=-12(11x-12)+8

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Solution for 7(-2+4x)+6=-12(11x-12)+8 equation: 



7(-2+4x)+6=-12(11x-12)+8

We move all terms to the left:

7(-2+4x)+6-(-12(11x-12)+8)=0

We add all the numbers together, and all the variables

7(4x-2)-(-12(11x-12)+8)+6=0

We multiply parentheses

28x-(-12(11x-12)+8)-14+6=0



We calculate terms in parentheses: -(-12(11x-12)+8), so:

-12(11x-12)+8

We multiply parentheses

-132x+144+8

We add all the numbers together, and all the variables

-132x+152

Back to the equation:

-(-132x+152)



We add all the numbers together, and all the variables

28x-(-132x+152)-8=0

We get rid of parentheses

28x+132x-152-8=0

We add all the numbers together, and all the variables

160x-160=0

We move all terms containing x to the left, all other terms to the right

160x=160

x=160/160

x=1

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