(5y+64)=(20+2y)

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Solution for (5y+64)=(20+2y) equation: 



(5y+64)=(20+2y)

We move all terms to the left:

(5y+64)-((20+2y))=0

We add all the numbers together, and all the variables

(5y+64)-((2y+20))=0

We get rid of parentheses

5y-((2y+20))+64=0



We calculate terms in parentheses: -((2y+20)), so:

(2y+20)

We get rid of parentheses

2y+20

Back to the equation:

-(2y+20)



We get rid of parentheses

5y-2y-20+64=0

We add all the numbers together, and all the variables

3y+44=0

We move all terms containing y to the left, all other terms to the right

3y=-44

y=-44/3

y=-14+2/3

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