15=4+4(2d-3)

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Solution for 15=4+4(2d-3) equation: 



15=4+4(2d-3)

We move all terms to the left:

15-(4+4(2d-3))=0



We calculate terms in parentheses: -(4+4(2d-3)), so:

4+4(2d-3)

determiningTheFunctionDomain
4(2d-3)+4

We multiply parentheses

8d-12+4

We add all the numbers together, and all the variables

8d-8

Back to the equation:

-(8d-8)



We get rid of parentheses

-8d+8+15=0

We add all the numbers together, and all the variables

-8d+23=0

We move all terms containing d to the left, all other terms to the right

-8d=-23

d=-23/-8

d=2+7/8

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