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6z=4(1/2z-7
We move all terms to the left:
6z-(4(1/2z-7)=0
Domain of the equation: 2z-7)!=0We multiply all the terms by the denominator
z∈R
6z*2z-7)-(4(1=0
We add all the numbers together, and all the variables
6z*2z=0
Wy multiply elements
12z^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$z=\frac{-b}{2a}=\frac{0}{24}=0$
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