-6(v+1)=2(1-3v)+8

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Solution for -6(v+1)=2(1-3v)+8 equation: 



-6(v+1)=2(1-3v)+8

We move all terms to the left:

-6(v+1)-(2(1-3v)+8)=0

We add all the numbers together, and all the variables

-6(v+1)-(2(-3v+1)+8)=0

We multiply parentheses

-6v-(2(-3v+1)+8)-6=0



We calculate terms in parentheses: -(2(-3v+1)+8), so:

2(-3v+1)+8

We multiply parentheses

-6v+2+8

We add all the numbers together, and all the variables

-6v+10

Back to the equation:

-(-6v+10)



We get rid of parentheses

-6v+6v-10-6=0

We add all the numbers together, and all the variables

-16!=0

There is no solution for this equation

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