6z-4+7z=3-z

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Solution for 6z-4+7z=3-z equation: 



6z-4+7z=3-z

We move all terms to the left:

6z-4+7z-(3-z)=0

We add all the numbers together, and all the variables

6z+7z-(-1z+3)-4=0

We add all the numbers together, and all the variables

13z-(-1z+3)-4=0

We get rid of parentheses

13z+1z-3-4=0

We add all the numbers together, and all the variables

14z-7=0

We move all terms containing z to the left, all other terms to the right

14z=7

z=7/14

z=1/2

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