6z-3(3z-2)=3(3-z)

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Solution for 6z-3(3z-2)=3(3-z) equation: 



6z-3(3z-2)=3(3-z)

We move all terms to the left:

6z-3(3z-2)-(3(3-z))=0

We add all the numbers together, and all the variables

6z-3(3z-2)-(3(-1z+3))=0

We multiply parentheses

6z-9z-(3(-1z+3))+6=0



We calculate terms in parentheses: -(3(-1z+3)), so:

3(-1z+3)

We multiply parentheses

-3z+9

Back to the equation:

-(-3z+9)



We add all the numbers together, and all the variables

-3z-(-3z+9)+6=0

We get rid of parentheses

-3z+3z-9+6=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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