6z+2=4(z-7)

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Solution for 6z+2=4(z-7) equation: 



6z+2=4(z-7)

We move all terms to the left:

6z+2-(4(z-7))=0



We calculate terms in parentheses: -(4(z-7)), so:

4(z-7)

We multiply parentheses

4z-28

Back to the equation:

-(4z-28)



We get rid of parentheses

6z-4z+28+2=0

We add all the numbers together, and all the variables

2z+30=0

We move all terms containing z to the left, all other terms to the right

2z=-30

z=-30/2

z=-15

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