3/4(x-4)=2/3(x+1)

Solution for 3/4(x-4)=2/3(x+1) equation:

3/4(x-4)=2/3(x+1)

We move all terms to the left:

3/4(x-4)-(2/3(x+1))=0


Domain of the equation: 4(x-4)!=0

x∈R



Domain of the equation: 3(x+1))!=0

x∈R


We calculate fractions


(9xx/(4(x-4)*3(x+1)))+(-8xx/(4(x-4)*3(x+1)))=0


We calculate terms in parentheses: +(9xx/(4(x-4)*3(x+1))), so:

9xx/(4(x-4)*3(x+1))

We multiply all the terms by the denominator


9xx

Back to the equation:

+(9xx)



We calculate terms in parentheses: +(-8xx/(4(x-4)*3(x+1))), so:

-8xx/(4(x-4)*3(x+1))

We multiply all the terms by the denominator


-8xx

Back to the equation:

+(-8xx)


We get rid of parentheses

9xx-8xx=0