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1/5d-1/5=2-2/5
We move all terms to the left:
1/5d-1/5-(2-2/5)=0
Domain of the equation: 5d!=0We add all the numbers together, and all the variables
d!=0/5
d!=0
d∈R
1/5d-1/5-(-2/5+2)=0
We get rid of parentheses
1/5d-2-1/5+2/5=0
We calculate fractions
-2!=0
There is no solution for this equation
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