6z+28=9z-2

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Solution for 6z+28=9z-2 equation: 



6z+28=9z-2

We move all terms to the left:

6z+28-(9z-2)=0

We get rid of parentheses

6z-9z+2+28=0

We add all the numbers together, and all the variables

-3z+30=0

We move all terms containing z to the left, all other terms to the right

-3z=-30

z=-30/-3

z=+10

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