6z+17=3(2z+4)

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Solution for 6z+17=3(2z+4) equation: 



6z+17=3(2z+4)

We move all terms to the left:

6z+17-(3(2z+4))=0



We calculate terms in parentheses: -(3(2z+4)), so:

3(2z+4)

We multiply parentheses

6z+12

Back to the equation:

-(6z+12)



We get rid of parentheses

6z-6z-12+17=0

We add all the numbers together, and all the variables

5!=0

There is no solution for this equation

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