6y-3(1-4y)=2(2-3y)+4

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Solution for 6y-3(1-4y)=2(2-3y)+4 equation: 



6y-3(1-4y)=2(2-3y)+4

We move all terms to the left:

6y-3(1-4y)-(2(2-3y)+4)=0

We add all the numbers together, and all the variables

6y-3(-4y+1)-(2(-3y+2)+4)=0

We multiply parentheses

6y+12y-(2(-3y+2)+4)-3=0



We calculate terms in parentheses: -(2(-3y+2)+4), so:

2(-3y+2)+4

We multiply parentheses

-6y+4+4

We add all the numbers together, and all the variables

-6y+8

Back to the equation:

-(-6y+8)



We add all the numbers together, and all the variables

18y-(-6y+8)-3=0

We get rid of parentheses

18y+6y-8-3=0

We add all the numbers together, and all the variables

24y-11=0

We move all terms containing y to the left, all other terms to the right

24y=11

y=11/24

y=11/24

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