(3x/x+1)-8=(-3x/x-1)

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Solution for (3x/x+1)-8=(-3x/x-1) equation: 



(3x/x+1)-8=(-3x/x-1)

We move all terms to the left:

(3x/x+1)-8-((-3x/x-1))=0



Domain of the equation: x+1)!=0

x∈R





Domain of the equation: x-1))!=0

x∈R



We get rid of parentheses

3x/x-((-3x/x-1))+1-8=0

We calculate fractions


3x^2/x^2+(-((-3x*x)/x^2+1-8=0

We calculate fractions

We do not support expression: x^4

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