6y+3-2(-4y-3)=2(y-3)

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Solution for 6y+3-2(-4y-3)=2(y-3) equation: 



6y+3-2(-4y-3)=2(y-3)

We move all terms to the left:

6y+3-2(-4y-3)-(2(y-3))=0

We multiply parentheses

6y+8y-(2(y-3))+6+3=0



We calculate terms in parentheses: -(2(y-3)), so:

2(y-3)

We multiply parentheses

2y-6

Back to the equation:

-(2y-6)



We add all the numbers together, and all the variables

14y-(2y-6)+9=0

We get rid of parentheses

14y-2y+6+9=0

We add all the numbers together, and all the variables

12y+15=0

We move all terms containing y to the left, all other terms to the right

12y=-15

y=-15/12

y=-1+1/4

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