125=(2x-2)+(4x+1)

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Solution for 125=(2x-2)+(4x+1) equation: 



125=(2x-2)+(4x+1)

We move all terms to the left:

125-((2x-2)+(4x+1))=0



We calculate terms in parentheses: -((2x-2)+(4x+1)), so:

(2x-2)+(4x+1)

We get rid of parentheses

2x+4x-2+1

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We get rid of parentheses

-6x+1+125=0

We add all the numbers together, and all the variables

-6x+126=0

We move all terms containing x to the left, all other terms to the right

-6x=-126

x=-126/-6

x=+21

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