6y+10=2(4y-3)

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Solution for 6y+10=2(4y-3) equation: 



6y+10=2(4y-3)

We move all terms to the left:

6y+10-(2(4y-3))=0



We calculate terms in parentheses: -(2(4y-3)), so:

2(4y-3)

We multiply parentheses

8y-6

Back to the equation:

-(8y-6)



We get rid of parentheses

6y-8y+6+10=0

We add all the numbers together, and all the variables

-2y+16=0

We move all terms containing y to the left, all other terms to the right

-2y=-16

y=-16/-2

y=+8

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