(x+2)2+x(x+1)=(x+3)2+x2

Solution for (x+2)2+x(x+1)=(x+3)2+x2 equation:

(x+2)2+x(x+1)=(x+3)2+x2

We move all terms to the left:

(x+2)2+x(x+1)-((x+3)2+x2)=0

We multiply parentheses

x^2+2x+x-((x+3)2+x2)+4=0


We calculate terms in parentheses: -((x+3)2+x2), so:

(x+3)2+x2

We add all the numbers together, and all the variables

x^2+(x+3)2

We multiply parentheses

x^2+2x+6

Back to the equation:

-(x^2+2x+6)


We add all the numbers together, and all the variables

x^2+3x-(x^2+2x+6)+4=0

We get rid of parentheses

x^2-x^2+3x-2x-6+4=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2