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6x^2-53x=9
We move all terms to the left:
6x^2-53x-(9)=0
a = 6; b = -53; c = -9;
Δ = b2-4ac
Δ = -532-4·6·(-9)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-55}{2*6}=\frac{-2}{12} =-1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+55}{2*6}=\frac{108}{12} =9 $
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