3x(2x+1)=630

Solution for 3x(2x+1)=630 equation:

3x(2x+1)=630

We move all terms to the left:

3x(2x+1)-(630)=0

We multiply parentheses

6x^2+3x-630=0

a = 6; b = 3; c = -630;
Δ = b2-4ac
Δ = 32-4·6·(-630)
Δ = 15129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15129}=123$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-123}{2*6}=\frac{-126}{12}
=-10+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+123}{2*6}=\frac{120}{12}
=10
$