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6x^2-4=22x
We move all terms to the left:
6x^2-4-(22x)=0
a = 6; b = -22; c = -4;
Δ = b2-4ac
Δ = -222-4·6·(-4)
Δ = 580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{145}}{2*6}=\frac{22-2\sqrt{145}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{145}}{2*6}=\frac{22+2\sqrt{145}}{12} $
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