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(2x-5)+(x+3)=120
We move all terms to the left:
(2x-5)+(x+3)-(120)=0
We get rid of parentheses
2x+x-5+3-120=0
We add all the numbers together, and all the variables
3x-122=0
We move all terms containing x to the left, all other terms to the right
3x=122
x=122/3
x=40+2/3
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